HackerRank JavaChallenges - Java If-Else

Task
Given an integer, , perform the following conditional actions:
  • If is odd, print Weird
  • If is even and in the inclusive range of to , print Not Weird
  • If is even and in the inclusive range of to , print Weird
  • If is even and greater than , print Not Weird
Complete the stub code provided in your editor to print whether or not is weird.
Input Format
A single line containing a positive integer, .
Constraints
  •  
Output Format
Print Weird if the number is weird; otherwise, print Not Weird.
Sample Input 0
3
Sample Output 0
Weird
Sample Input 1
24
Sample Output 1
Not Weird
Explanation
Sample Case 0:
is odd and odd numbers are weird, so we print Weird.
Sample Case 1:
and is even, so it isn't weird. Thus, we print Not Weird.


Solution:

    import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {

            Scanner sc=new Scanner(System.in);
            int n=sc.nextInt();           
            String ans="";
            if(n%2==1){
              ans = "Weird";
            }
            else {
                if (n >= 2 && n <= 5) {
                    ans = "Not Weird";
                } else if (n >= 6 && n <= 20) {
                    ans = "Weird";
                } else {
                    ans = "Not Weird";
                }
            }
            System.out.println(ans);  
             
        }

    }


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